2x^2/3-3x^1/3-35=0

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Solution for 2x^2/3-3x^1/3-35=0 equation: 


x in (-oo:+oo)

(2*x^2)/3-((3*x^1)/3)-35 = 0

(2*x^2)/3-x-35 = 0

2/3*x^2-x-35 = 0

DELTA = (-1)^2-(-35*2/3*4)

DELTA = 283/3

DELTA > 0

x = ((283/3)^(1/2)+1)/(2/3*2) or x = (1-(283/3)^(1/2))/(2/3*2)

x = 3/4*((283/3)^(1/2)+1) or x = 3/4*(1-(283/3)^(1/2))

x in { 3/4*(1-(283/3)^(1/2)), 3/4*((283/3)^(1/2)+1) }

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